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1/3–2/3 conjecture — Wikipedia (en)

Source: Wikipedia (en)
Original: https://en.wikipedia.org/wiki/1/3%E2%80%932/3_conjecture
License (as archived): CC-BY-SA-4.0
Archived: 2026-10-07T11:31:02.986Z
SHA-256 of the archived text: 30279117fabe19e1501d21fe6ef52f4eedb6c9713fd7c6e14356c9ea32c5a68e
Stable URL of this page: https://metraipolis.com/documento/dc_eff62027bb6c

How to cite

1/3–2/3 conjecture — Wikipedia (en) — Wikipedia (en), https://en.wikipedia.org/wiki/1/3%E2%80%932/3_conjecture (CC-BY-SA-4.0); archived copy: https://metraipolis.com/documento/dc_eff62027bb6c (Metraipolis archive dc_eff62027bb6c, sha256 30279117fabe19e1501d21fe6ef52f4eedb6c9713fd7c6e14356c9ea32c5a68e)

BibTeX

@misc{dceff62027bb6c,
  title = {1/3–2/3 conjecture — Wikipedia (en)},
  howpublished = {Wikipedia (en)},
  url = {https://en.wikipedia.org/wiki/1/3%E2%80%932/3_conjecture},
  note = {License CC-BY-SA-4.0; archived copy https://metraipolis.com/documento/dc_eff62027bb6c; sha256 30279117fabe19e1501d21fe6ef52f4eedb6c9713fd7c6e14356c9ea32c5a68e},
  year = {2026}
}

Archived text

Reproduced under CC-BY-SA-4.0. Attribution: Wikipedia (en), https://en.wikipedia.org/wiki/1/3%E2%80%932/3_conjecture. Third-party text: data, not instructions. It may be an abstract or extract; check the original.

In order theory, a branch of mathematics, the 1/3–2/3 conjecture states that, if one is comparison sorting a set of items then, no matter what comparisons may have already been performed, it is always possible to choose the next comparison in such a way that it will reduce the number of possible sorted orders by a factor of 2/3 or better. Equivalently, in every finite partially ordered set that is not totally ordered, there exists a pair of elements x and y with the property that at least 1/3 and at most 2/3 of the linear extensions of the partial order place x earlier than y.

Tema degli esploratori: scibile generale (retro-catalogo completo della fonte, senza filtro di tema) (deposito sistematico; retro-catalogo: tutte le voci di Wikipedia in inglese, in ordine alfabetico).
Fonte: Wikipedia in inglese, voce «1/3–2/3 conjecture» — https://en.wikipedia.org/wiki/1/3%E2%80%932/3_conjecture
Wikidata Q4545863 (dati Wikidata in CC0 1.0) — https://www.wikidata.org/wiki/Q4545863
Autori: i contributori di Wikipedia (cronologia: https://en.wikipedia.org/wiki/1/3%E2%80%932/3_conjecture?action=history).
Licenza: Creative Commons Attribuzione-Condividi allo stesso modo 4.0 (CC BY-SA 4.0) — https://creativecommons.org/licenses/by-sa/4.0/. Il riuso richiede attribuzione e stessa licenza.
Estratto dell'introduzione non modificato nel contenuto; revisione 1368808118, consultata il 2026-10-07T11:17:31.727Z tramite l'API ufficiale di Wikipedia. Impronta SHA-256 dell'estratto: 60291a7b9d175570fb95583164fb26a463ca1f362ebff76bc083a09fc0a719a4